3j^2-2j+12=0

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Solution for 3j^2-2j+12=0 equation:


Simplifying
3j2 + -2j + 12 = 0

Reorder the terms:
12 + -2j + 3j2 = 0

Solving
12 + -2j + 3j2 = 0

Solving for variable 'j'.

Begin completing the square.  Divide all terms by
3 the coefficient of the squared term: 

Divide each side by '3'.
4 + -0.6666666667j + j2 = 0

Move the constant term to the right:

Add '-4' to each side of the equation.
4 + -0.6666666667j + -4 + j2 = 0 + -4

Reorder the terms:
4 + -4 + -0.6666666667j + j2 = 0 + -4

Combine like terms: 4 + -4 = 0
0 + -0.6666666667j + j2 = 0 + -4
-0.6666666667j + j2 = 0 + -4

Combine like terms: 0 + -4 = -4
-0.6666666667j + j2 = -4

The j term is -0.6666666667j.  Take half its coefficient (-0.3333333334).
Square it (0.1111111112) and add it to both sides.

Add '0.1111111112' to each side of the equation.
-0.6666666667j + 0.1111111112 + j2 = -4 + 0.1111111112

Reorder the terms:
0.1111111112 + -0.6666666667j + j2 = -4 + 0.1111111112

Combine like terms: -4 + 0.1111111112 = -3.8888888888
0.1111111112 + -0.6666666667j + j2 = -3.8888888888

Factor a perfect square on the left side:
(j + -0.3333333334)(j + -0.3333333334) = -3.8888888888

Can't calculate square root of the right side.

The solution to this equation could not be determined.

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